manhn29112005 manhn29112005

03-08-2021
Mathematics

contestada

[tex](cos^{2} x-sin^{2}x)^{2} -sin4x+sin^{2}2x=0[/tex]

Respuesta :

Аноним Аноним

03-08-2021

Answer:

x=22.5°

Step-by-step explanation:

(cos²x-sin²x)-sin4x+sin²2x=0

or, (cos2x)²-sin4x+sin²2x=0

or, cos²2x+sin²2x-sin4x=0

or, 1-sin4x=0

or, sin4x=1

or, 4x=90°

or, x=90°/4

or, x=22.5°

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