tbird1270 tbird1270

01-08-2020
Mathematics

contestada

Compute the values of dy and Δy for the function y=e^(2x)+6x given x=0 and Δx=dx=0.03.

Respuesta :

sqdancefan sqdancefan

01-08-2020

Answer:

dy = 8·dx
Δy = 0.24

Step-by-step explanation:

The derivative of your function is ...

y' = dy/dx = 2e^(2x) +6

At x=0, the value is ...

y'(0) = 2e^0 +6 = 8

dy = 8·dx

__

Δy = y'(0)·Δx

Δy = 8(.03)

Δy = 0.24

Answer Link

Otras preguntas

it is said that the protoplasm cannat be analysed chemically.Why?

Show that each algebraic fraction simplifies to the given expression. a) 2/x+1 + 5/x+2 = 3 simplifies to 3x² + 2x - 3 = 0 b) 3/4x+1 - 4/x+2 = 2 simplifies to 8

there are three source of resistance in parallel circuit. Two of them are rated at 20 ohms, the other at 10 ohms. What is the circuits total resistance

Element A has 15 protons. Determine the number of neutrons in its isotope with mass number 33.

can somone give me the answer to 2 x 0

In creative nonfiction a quote is differentiated from fictional dialogue in that it

what illness did samuel coleridge battle with?

Why was Head Start important in the history of teacher aides? A. It helped recruit white women and men to act as role models. B. It was one of the first progra

the calculation of property tax is based on the

Who is William lots garrison