lilman1900 lilman1900
  • 03-07-2018
  • Mathematics
contestada

write an equation of a line that is perpendicular -3x -6y=17, (6,3)

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DeanR
DeanR DeanR
  • 03-07-2018

I'll assume that (6,3) at the end means we want the pependicular through (6,3)

The perpendicular is gotten by swapping the coefficients on x and y and negating one; it doesn't matter which.  The point it goes through sets the constant straightforwardly:

6x - 3y = 6(6) - 3(3) = 27

6x - 3y = 27  is the perpendicular



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