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01-06-2018
Mathematics

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how can i solve this equation?
Sin
[tex] sin^{3}x + 3sin {}^{2} x + 2 \sin x = 0[/tex]
Please help me if you can

how can i solve this equationSintex sin3x 3sin 2 x 2 sin x 0texPlease help me if you can class=

Respuesta :

NabasishGogoi NabasishGogoi

01-06-2018

Factorizing sin2x+3sinx+2=0

sin^2 x+2sinx+sinx+2=0

or sinx(sinx+2)+1(sinx+2)=0

or (sinx+1)(sinx+2)=0

Now as sinx+2≠0, we have sinx+1=0

or sinx= −1 =sin(3π/2)

Hence, x=2nπ+3π/2

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