Respuesta :

1. n/2-1/3-1=1/6
n/2=1/6+1/3+1
n/2=1/6+2/6+6/6
n/2=9/6=3/2
n=3/2*2=3

check: abs(3/2-1/3)-1=1/6,    abs(9/6-2/6)-1= 1/6, 7/6-1=1/6, 1/6 =1/6 
3 is a root

2. -(n/2-1/3)-1=1/6
-n/2+1/3-1=1/6
-n/2-2/3=1/6
-n/2=1/6+2/3
-n/2=1/6+4/6
-n/2=5/6
n=-2*5/6=-5/3=-1 2/3  
check :    abs((-5/3)/2-1/3) -1=1/6
abs(-5/6-1/3) -1 =1/6,     abs(-5/6-2/6) -1=1/6, abs (-7/6)-1=1/6,  7/6-1=1/6, 1/6=1/6
so -5/3 or -1 2/3  is also root

so  two roots 3 and -5/3(that can be written as -1 2/3)

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